February 25, 2021

Garbine Muguruza continues performance in Melbourne

The 18th World No., Spanish tennis player Garbine Muguruza, in the third round of the Australian Open defeated Swiss Timea Bacsinszky, who is 145th in the world ranking, – 7/6 (5), 6/2.

For 1 hour and 54 minutes of the match, Garbine made one ace and five breaks, having mistaken twice when serving. Whereas, Timea filed three times right through and implemented three break points, making three double faults.

Through personal meetings, opponents became 5: 1 in favor of the Spaniard. In the fourth round of the Australian Open, he will play with Czech Karolina Pliskova.

Spread the love

Leave a Reply