Last Updated on February 28, 2019
The third racket of the world, German Alexander Zverev, beat Spaniard David Ferrer, occupying the 145th line of the ATP rating, with a score of 7/6 (0), 6/1 in the second round of the tournament in Acapulco. The match lasted 1 hour and 28 minutes.
During this time, the 21-year-old Zverev completed nine aces, made a mistake six times in filing and sold three break points, while the 36-year-old Ferrer never gave a pass through, made two double mistakes and made one break.
Previously, the score in personal meetings was 4: 2 in favor of the German. In the quarterfinals of the Abierto Mexicano TELCEL competition, Zverev will face Australian Alex De Minaur.
